\[\boxed{\mathbf{876\ (876).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[b_{n} = 10 \cdot 3^{n - 1}\]
\[b_{1} = 10 \cdot 3^{1 - 1} = 10\ \ \]
\[b_{2} = 10 \cdot 3^{2 - 1} = 10 \cdot 3 =\]
\[= 30 \Longrightarrow \ \ q = \frac{30}{10} = 3\]
\[S_{5} = \frac{10 \cdot \left( 3^{5} - 1 \right)}{3 - 1} =\]
\[= \frac{10 \cdot (243 - 1)}{2} =\]
\[= 5 \cdot 242 = 1210.\]
\[Ответ:1210.\]