\[\boxed{\mathbf{828\ (828).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[b_{1} = \frac{1}{125};\ \ q = 5\]
\[1)\ b_{4} = b_{1} \cdot q³ = \frac{1}{125} \cdot (5)^{3} =\]
\[= \frac{125}{125} = 1;\]
\[2)\ b_{7} = b_{1} \cdot q^{6} = \frac{1}{125} \cdot (5)^{6} =\]
\[= \frac{5^{6}}{5^{3}} = 5³ = 125.\]