\[\boxed{\mathbf{821\ (821).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[1)\ b_{12} = 24;\ b_{13} = 4\]
\[b_{13} = b_{12} \cdot q\ \ \]
\[q = \frac{b_{13}}{b_{12}} = \frac{4}{24} = \frac{1}{6}.\]
\[2)\ b_{4} = - \frac{2}{9};\ \ b_{5} = \frac{4}{15}\]
\[b_{5} = b_{4} \cdot q\ \ \]
\[q = \frac{b_{5}}{b_{4}} = - \frac{4 \cdot 9}{15 \cdot 2} = - \frac{6}{5}.\]