Решебник по алгебре 9 класс Мерзляк Задание 820

\[\boxed{\mathbf{820\ (820).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ b_{1} = 6;\ \ b_{2} = - 3\]

\[b_{2} = b_{1}\text{q\ \ }\]

\[q = \frac{b_{2}}{b_{1}} = - \frac{3}{6} = - \frac{1}{2}.\]

\[2)\ b_{7} = - 9;\ \ b_{8} = 15\]

\[b_{8} = b_{7}\text{q\ }\]

\[q = \frac{b_{8}}{b_{7}} = \frac{15}{- 9} = \frac{5}{- 3} = - 1\frac{2}{3}.\]

\[3)\ b_{10} = 3\sqrt{3};\ \ b_{11} = 9\]

\[b_{11} = b_{10}q\]

\[\ \ q = \frac{b_{11}}{b_{10}} = \frac{9}{3\sqrt{3}} = \frac{3}{\sqrt{3}} =\]

\[= \frac{3\sqrt{3}}{3} = \sqrt{3}.\]