\[\boxed{\mathbf{801\ (801).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[a_{1} = 100;\ \ S_{6} = 5 \cdot S_{7 - 12}\]
\[S_{6} = \frac{2cc + 5d}{2} \cdot 6 =\]
\[= (2 \cdot 100 + 5d) \cdot 3 =\]
\[= (200 + 5d) \cdot 3\]
\[(200 + 5d) \cdot 3 = 5 \cdot S_{7 - 12}\]
\[S_{7 - 12} = \frac{2a_{7} + 5d}{2} \cdot 6 =\]
\[= \left( 2 \cdot \left( a_{1} + 6d \right) + 5d \right) \cdot 3 =\]
\[= \left( 2a_{1} + 12d + 5d \right) \cdot 3 =\]
\[= \left( 2a_{1} + 17d \right) \cdot 3 =\]
\[= (200 + 17d) \cdot 3\]
\[(200 + 5d) \cdot 3 =\]
\[= 5 \cdot (200 + 17d) \cdot 3\ \ \ \ \ |\ :3\]
\[200 + 5d = 1000 + 85d\]
\[80d = - 800,\ \ d = - 10\]
\[Ответ:\ d = - 10.\]