Решебник по алгебре 9 класс Мерзляк Задание 527

 

\[\boxed{\mathbf{527\ (527).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[44\ 100 = 40\ 000 \cdot \left( 1 + \frac{p}{100} \right)^{2}\]

\[\left( 1 + \frac{p}{100} \right)^{2} = \frac{44100}{40000}\]

\[1 + \frac{p}{100} = \sqrt{1,1025}\]

\[1 + \frac{p}{100} = 1,05\]

\[\frac{p}{100} = 0,05\]

\[p = 5\]

\[5\% - ежегодный\ процент\ \]

\[прироста\ населения.\]

\[Ответ:5\%.\]

\[\boxed{\mathbf{527.\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ a_{n} = n + 4\]

\[a_{1} = 1 + 4 = 5\]

\[a_{2} = 2 + 4 = 6\]

\[a_{3} = 3 + 4 = 7\]

\[a_{4} = 4 + 4 = 8\]

\[2)\ a_{n} = 4n - 3\]

\[a_{1} = 4 - 3 = 1\]

\[a_{2} = 8 - 3 = 5\]

\[a_{3} = 12 - 3 = 9\]

\[a_{4} = 16 - 3 = 13\]

\[3)\ a_{n} = \frac{n}{n² + 1}\]

\[a_{1} = \frac{1}{2}\]

\[a_{2} = \frac{2}{4 + 1} = \frac{2}{5}\]

\[a_{3} = \frac{3}{9 + 1} = \frac{3}{10}\]

\[a_{4} = \frac{4}{16 + 1} = \frac{4}{17}\]

\[4)\ a_{n} = \frac{2^{n}}{n}\]

\[a_{1} = \frac{2}{1} = 2\]

\[a_{2} = \frac{4}{2} = 2\]

\[a_{3} = \frac{8}{3}\]

\[a_{4} = \frac{16}{4} = 4\]