\[\boxed{\text{356\ (356).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[y = 2x^{2} - 3x + 6;\ \ \ y = x + 12\]
\[- 2x^{2} - 3x + 6 = x + 12\]
\[2x^{2} - 4x - 6 = 0\ \ |\ :2\]
\[x^{2} - 2x - 3 = 0\]
\[x_{1} + x_{2} = 2,\ \ x_{1}x_{2} = - 3,\ \ \]
\[x_{1} = - 1,\ \ x_{2} = 3.\]
\[x = - 1 \rightarrow \ \ y = 11\]
\[x = 3 \rightarrow \ y = 15.\]
\[Ответ:( - 1;11),\ (3;15).\]