Решебник по алгебре 9 класс Мерзляк Задание 334

 

\[\boxed{\text{334\ (334).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ y = \frac{3x + 8}{x}\]

\[y = \frac{3x}{x} + \frac{8}{x}\]

\[y = \frac{8}{x} + 3;\ \ x \neq 0\]

\[1)\ y = \frac{8}{x}\]

\[2)\ y = \frac{2x + 14}{x + 3}\]

\[y = \frac{2(x + 3) + 8}{x + 3}\]

\[y = \frac{8}{x + 3} + 2;\ \ x \neq - 3\]

\[1)\ y = \frac{8}{x}\]

\[2)\ y = \frac{8}{x + 3}\]

\[3)\ y = \frac{- 2x}{x - 1}\]

\[y = \frac{- 2x + 2 - 2}{x - 1}\]

\[y = \frac{- 2(x - 1) - 2}{x - 1}\]

\[y = \frac{- 2}{x - 1} - 2\]

\[1)\ y = - \frac{2}{x}\]

\[2)\ y = - \frac{2}{x - 1}\]

\[\boxed{\text{334.}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ h(x) = 9 - 10x\]

\[Пересекает\ ось\ \ y:\text{\ \ }\]

\[h(0) = 9.\]

\[Пересекает\ ось\ x:\]

\[9 - 10x = 0\]

\[10x = 9\]

\[x = 0,9\]

\[Ответ:(0;9);\ (0,9;0).\]

\[2)\ p(x) = 4x^{2} + x - 3\]

\[Пересекает\ ось\ y:\ \ \]

\[p(0) = - 3.\]

\[Пересекает\ ось\ x:\]

\[4x^{2} + x - 3 = 0\]

\[D = 1 + 48 = 49\]

\[x = \frac{- 1 + 7}{8} = \frac{3}{4}\]

\[x = \frac{- 1 - 7}{8} = - 1\]

\[Ответ:( - 1;0);\ \left( \frac{3}{4};0 \right);\ (0;\ - 3).\]

\[3)\ s(x) = \frac{x^{2} - 2}{x^{2} + 2}\]

\[Пересекает\ ось\ x:\ \]

\[\frac{x^{2} - 2}{x^{2} + 2} = 0\]

\[x^{2} = 2\]

\[x = \pm \sqrt{2}.\]

\[Пересекает\ ось\ y:\text{\ \ }\]

\[s(0) = \frac{- 2}{2} = - 1.\]

\[Ответ:(0;\ - 1);\ \]

\[\left( \sqrt{2};0 \right);\ \left( - \sqrt{2};0 \right)\text{.\ }\]