\[\boxed{\text{85\ (85).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[1)\ \frac{x + 3}{x} = \frac{x}{x} + \frac{3}{x} = 1 + \frac{3}{x}\]
\[2)\ \frac{a^{2} - 2a - 5}{a - 2} = \frac{a^{2} - 2a}{a - 2} -\]
\[- \frac{5}{a - 2} = \frac{a(a - 2)}{(a - 2)} - \frac{5}{a - 2} =\]
\[= a - \frac{5}{a - 2}\]
\[\boxed{\text{85.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[\frac{x}{y} = 4\]
\[1)\ \frac{y}{x} = \frac{1}{4}\]
\[2)\ \frac{2x - 3y}{y} = \frac{2x}{y} - \frac{3y}{y} =\]
\[= \frac{2x}{y} - 3 = 2 \cdot \frac{x}{y} - 3 = 2 \cdot 4 - 3 =\]
\[= 8 - 3 = 5\]
\[3)\ \frac{x^{2} + y^{2}}{\text{xy}} = \frac{x^{2}}{\text{xy}} + \frac{y^{2}}{\text{xy}} = \frac{x}{y} + \frac{y}{x} =\]
\[= 4 + \frac{1}{4} = 4\frac{1}{4} = 4,25\]