\[\boxed{\mathbf{780\ (780).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[\left\{ \begin{matrix} (3x - 1)^{2} = t\ \ \ \ \ \ \ \ \\ t^{2} - 20t + 64 = 0 \\ \end{matrix} \right.\ \]
\[t_{1} + t_{2} = 20,\ \ t_{1} \cdot t_{2} = 64,\ \]
\[\ t_{1} = 4,\ \ t_{2} = 16\]
\[Ответ:\ x = \pm 1;\ x = - \frac{1}{3};x = \ \frac{5}{3}.\]
\[\left\{ \begin{matrix} (2x + 3)^{2} = t\ \ \ \ \ \ \ \ \\ t² - 24t - 25 = 0 \\ \end{matrix} \right.\ \]
\[t_{1} + t_{2} = 24,\ \ t_{1} \cdot t_{2} = - 25,\ \]
\[\ t_{1} = - 1,\ \ t_{2} = 25\]
\[Ответ:\ x = - 4;x = 1.\]