Решебник по алгебре 8 класс Мерзляк Задание 717

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\[x_{1} = \frac{1}{3}\]

\[x_{2} = ?\]

\[6x² - bx + 4 = 0\ \ \ \ |\ :6\]

\[x² - \frac{b}{6}x + \frac{2}{3} = 0\]

\[\left\{ \begin{matrix} x_{2} + \frac{1}{3} = \frac{b}{6} \\ \frac{1}{3}x_{2} = \frac{2}{3}\text{\ \ \ } \\ \end{matrix} \right.\ \]

\[x_{2} = \frac{2 \cdot 3}{3 \cdot 1} = 2.\]

\[2 + \frac{1}{3} = \frac{b}{6}\text{\ \ \ }\]

\[\frac{7}{3} = \frac{b}{6}\text{\ \ }\]

\[3b = 42\]

\[b = 14\]

\[Ответ:x_{2} = 2;\ \ b = 14.\]