\[\boxed{\mathbf{673\ (673).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[x^{2} - 0,5ax - 3a^{2} = 0;\ \ x = 2\]
\[4 - a - 3a^{2} = 0\]
\[3a^{2} + a - 4 = 0\]
\[D = 1 + 48 = 49\]
\[a = \frac{- 1 \pm \sqrt{49}}{6} = \frac{- 1 \pm 7}{6}\]
\[a_{1} = 1\]
\[a_{2} = - \frac{4}{3} = - 1\frac{1}{3}\]
\[Ответ:при\ a = 1;\ a = - 1\frac{1}{3}.\]