Решебник по алгебре 8 класс Мерзляк ФГОС Задание 633

\[\boxed{\mathbf{633\ (633).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{x^{2} - 8x}{6} = x\ \ \ | \cdot 6\]

\[x^{2} - 8x = 6x\]

\[x^{2} - 14x = 0\]

\[x(x - 14) = 0\]

\[x = 0,\ \ x = 14\]

\[Ответ:x = 0;x = 14.\]

\[2)\ \frac{x^{2} - 3}{5} - \frac{x^{2} - 1}{2} = 2\]

\[\frac{2x^{2} - 6 - 5x^{2} + 5}{10} = 2\ \ \ | \cdot 10\]

\[- 3x^{2} - 1 = 20\]

\[- 3x^{2} = 21\]

\[x^{2} = - 7\]

\[Ответ:корней\ нет.\]

\[\boxed{\mathbf{63}\mathbf{3}\mathbf{\text{.\ }}Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \sqrt{\left( \sqrt{5} - 4 \right)^{2}} = \left| \sqrt{5} - 4 \right| =\]

\[= 4 - \sqrt{5}\]

\[2)\ \sqrt{\left( \sqrt{8} - 3 \right)^{2}} - \sqrt{\left( \sqrt{2} - 3 \right)^{2}} =\]

\[= \left| \sqrt{8} - 3 \right| - \left| \sqrt{2} - 3 \right| =\]

\[= - \sqrt{8} + 3 - 3 + \sqrt{2} =\]

\[= \sqrt{2} - \sqrt{8} = \sqrt{2} - 2\sqrt{2} = - \sqrt{2}\]