Решебник по алгебре 8 класс Мерзляк ФГОС Задание 528

\[\boxed{\mathbf{528\ (528).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 2\sqrt{6} = \sqrt{4 \cdot 6} = \sqrt{24};\]

\[2)\ 9\sqrt{2} = \sqrt{81 \cdot 2} = \sqrt{162};\]

\[3) - 11\sqrt{3} = - \sqrt{363};\]

\[4)\ 12\sqrt{b} = \sqrt{144b};\]

\[5) - 7\sqrt{3c} = - \sqrt{49 \cdot 3c} =\]

\[= - \sqrt{147c};\]

\[6) - 10\sqrt{0,7m} =\]

\[= - \sqrt{100 \cdot 0,7m} = - \sqrt{70m};\]

\[7)\ 8\ \sqrt{\frac{n}{8}} = \sqrt{64\frac{n}{8}} = \sqrt{8n};\]

\[8) - \frac{1}{3}\sqrt{18p} = - \sqrt{\frac{1}{9} \cdot 18p} =\]

\[= - \sqrt{2p}.\]

\[\boxed{\mathbf{5}\mathbf{2}\mathbf{8}\mathbf{\text{.\ }}Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{\sqrt{75}}{\sqrt{3}} = \sqrt{\frac{75}{3}} = \sqrt{25} = 5\]

\[2)\ \frac{\sqrt{98}}{\sqrt{2}} = \sqrt{49} = 7\]

\[3)\ \frac{\sqrt{3}}{\sqrt{48}} = \sqrt{\frac{1}{16}} = \frac{1}{4}\]

\[4)\ \frac{\sqrt{3,2}}{\sqrt{0,2}} = \sqrt{16} = 4\]

\[5)\ \frac{\sqrt{72}}{\sqrt{50}} = \sqrt{1,44} = 1,2\]

\[6)\ \frac{\sqrt{27}}{\sqrt{147}} = \frac{\sqrt{9}}{\sqrt{49}} = \frac{3}{7}\]

\[7)\ \frac{\sqrt{6} \cdot \sqrt{3}}{\sqrt{2}} = \frac{\sqrt{18}}{\sqrt{2}} = \sqrt{9} = 3\]

\[8)\ \frac{\sqrt{5}}{\sqrt{3} \cdot \sqrt{15}} = \frac{\sqrt{5}}{\sqrt{45}} = \sqrt{\frac{5}{45}} =\]

\[= \sqrt{\frac{1}{9}} = \frac{1}{3}\]