Решебник по алгебре 8 класс Мерзляк Задание 240

\[\boxed{\text{240\ (240).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[1)\ 5^{- 2} = \frac{1}{5^{2}} = \frac{1}{25}\]

\[2){\ 2}^{- 4} = \frac{1}{2^{4}} = \frac{1}{16}\]

\[3)\ ( - 9)^{- 2} = \frac{1}{( - 9)^{2}} = \frac{1}{81}\]

\[4)\ {0,2}^{- 3} = \frac{1}{{0,2}^{3}} = \frac{1}{0,008} =\]

\[= \frac{1000}{8} = 125\]

\[5)\ 1^{- 24} = \frac{1}{1^{24}} = 1\]

\[6)\ ( - 1)^{- 16} = \frac{1}{( - 1)^{16}} = 1\]

\[7)\ ( - 1)^{- 17} = \frac{1}{( - 1)^{17}} = - 1\]

\[8)\ \left( \frac{7}{8} \right)^{0} = 1\]

\[9)\ \left( \frac{2}{3} \right)^{- 3} = \frac{3^{3}}{2^{3}} = \frac{27}{8} = 3\frac{3}{8}\]

\[10)\ \left( - 1\frac{1}{6} \right)^{- 2} = \left( - \frac{7}{6} \right)^{- 2} =\]

\[= \frac{6^{2}}{7^{2}} = \frac{36}{49}\]