Решебник по алгебре 8 класс Мерзляк Задание 193

\[\boxed{\text{193\ (193).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ (3x - 1)(4x + 5) -\]

\[- (2x + 3)(6x + 1) = 4\]

\[12x^{2} + 15x - 4x - 5 - 12x^{2} -\]

\[- 2x - 18x - 3 - 4 = 0\]

\[- 9x = 12\]

\[x = - \frac{12}{9}\]

\[x = - \frac{4}{3}\]

\[x = - 1\frac{1}{3}\]

\[Ответ:\ x = - 1\frac{1}{3}.\]

\[2)\ 8x(2x + 7) - (4x + 3)^{2} = 15\]

\[16x^{2} + 56x - 16x^{2} - 24x -\]

\[- 9 - 15 = 0\]

\[32x = 24\]

\[x = \frac{24}{32}\]

\[x = \frac{3}{4}\]

\[Ответ:x = \frac{3}{4}.\]