\[\boxed{\mathbf{1146}\mathbf{\text{.\ }}Еуроки\ - \ ДЗ\ без\ мороки}\]
\[x^{2} - (2a - 5)x + a^{2} - 7 = 0\]
\[D = 4a^{2} - 20a + 25 - 4a^{2} + 28 =\]
\[= 53 - 20a \geq 0\]
\[20a \leq 53\]
\[a \leq \frac{53}{20}\]
\[a \leq 2,65\]
\[\left\{ \begin{matrix} x_{1} + x_{2} = 2a - 5 \\ x_{1}x_{2} = a^{2} - 7\ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ }\]
\[2x_{1} + 2x_{2} = x_{1} \cdot x_{2}\]
\[2 \cdot (2a - 5) = a^{2} - 7\]
\[- a^{2} + 4a - 3 = 0\]
\[a_{1} + a_{2} = 4;\ \ a_{1}a_{2} = 3,\ \ \]
\[a_{1} = 3;\ \ a_{2} = 1\]
\[a_{1} = 3 > 2,65\]
\[Ответ:при\ a = 1.\]