Решебник по алгебре 7 класс Мерзляк Задание 948

\[\boxed{\text{948\ (948).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[3m^{2}n = 2;\ \ \ \ \ n^{2}k^{4} = 3;\ \ \ \ \ \]

\[m^{2}n = \frac{2}{3}\]

\[1){\ \left( 3m^{2}n^{2}k^{2} \right)}^{2} =\]

\[= \left( 3m^{2}n \right)^{2} \cdot \left( nk^{2} \right)^{2} =\]

\[= 2² \cdot n^{2}k^{4} = 4 \cdot 3 = 12\]

\[2)\ \left( - 2m^{2}nk^{2} \right)^{3} \cdot \left( 0,5n^{2}k \right)^{2} =\]

\[= ( - 2)^{3} \cdot \left( m^{2}nk^{2} \right)^{3} \cdot \left( 0,5n^{2}k \right)^{2} =\]

\[= - 8 \cdot \left( m^{2}k \right)^{3} \cdot k^{6} \cdot \frac{1}{4}n^{4}k^{2} =\]

\[= - 8 \cdot \left( \frac{2}{3} \right)^{3} \cdot \frac{1}{4} \cdot n^{4}k^{8} =\]

\[= - 2 \cdot \frac{8}{27} \cdot \left( n^{2}k^{4} \right)^{2} =\]

\[= - 2 \cdot \frac{8}{27} \cdot 9 = \frac{- 2 \cdot 8 \cdot 9}{27} =\]

\[= - \frac{16}{3} = - 5\frac{1}{3}\]