\[\boxed{\text{801\ (801).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[y( - 1) = 1 + 2 = 3,\ \ \]
\[y( - 0,5) = 0,25 + 1 = 1,25\ \ \]
\[y(0) = 0\]
\[y(0,5) = 0,25 - 1 = - 0,75\ \ \]
\[y(1) = 1 - 2 = - 1\ \ \ \]
\[y(1,5) = 2,25 - 3 = - 0,75\]
\[y(2) = 4 - 4 = 0\ \ \]
\[y(2,5) = 6,25 - 5 = 1,25\ \ \]
\[y(3) = 9 - 6 = 3\]
\[x\] | \[- 1\] | \[- 0,5\] | \[0\] | \[0,5\] | \[1\] | \[1,5\] | \[2\] | \[2,5\] | \[3\] |
---|---|---|---|---|---|---|---|---|---|
\[y\] | \[3\] | \[1,25\] | \[0\] | \[- 0,75\] | \[- 1\] | \[- 0,75\] | \[0\] | \[1,25\] | \[3\] |
\[\boxed{\text{801.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[1)\ a^{3}b^{6} = (ab^{2})³\]
\[2)\ 8x^{3}y^{9} = (2xy^{3})³\]
\[3)\frac{1}{64}c^{9} = \left( \frac{1}{4}c^{3} \right)^{3}\]
\(4)\ 125m^{12}n^{21} = \left( 5m^{4}n^{7} \right)^{3}\)
\[5)\ 0,216k^{15}p^{24} = (0,6k^{5}p^{8})³\]
\[6)\ 0,008a^{9}b^{18}c^{27} =\]
\[= (0,2a^{3}b^{6}c^{9})³\]