\[\boxed{\text{681\ (681).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[1)\ \left( 9a^{2} + 3a + 1 \right)(3a - 1) =\]
\[= 27a³ - 1\]
\[при\ a = \frac{1}{3} \Longrightarrow 27 \cdot \frac{1}{27} - 1 =\]
\[= 1 - 1 = 0\]
\[2)\ (5y - 2)\left( 25y^{2} + 10y + 4 \right) + 8 =\]
\[= 125y³ - 8 + 8 = 125y³\]
\[при\ y = - \frac{1}{5} \Longrightarrow 125 \cdot \left( - \frac{1}{5} \right)^{3} =\]
\[= - \frac{125 \cdot 1}{125} = - 1\]