Решебник по алгебре 7 класс Мерзляк Задание 529

\[\boxed{\text{529\ (529).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ \frac{4x - 1}{12} - \frac{3x + 1}{8} =\]

\[= x + 1\ \ \ \ \ | \cdot 24\]

\[2 \cdot (4x - 1) - 3 \cdot (3x + 1) =\]

\[= 24 \cdot (x + 1)\]

\[8x - 2 - 9x - 3 = 24x + 24\]

\[- 25x = 29\]

\[x = - \frac{29}{25}\]

\[x = - 1\frac{4}{25}\]

\[Ответ:\ x = - 1\frac{4}{25}.\]

\[2)\ \frac{3x - 2}{9} - \frac{2x + 1}{6} =\]

\[= \frac{5 - x}{3}\ \ \ \ \ \ | \cdot 18\]

\[2 \cdot (3x - 2) - 3 \cdot (2x + 1) =\]

\[= 6 \cdot (5 - x)\]

\[6x - 4 - 6x - 3 = 30 - 6x\]

\[6x = 37\]

\[x = \frac{37}{6}\]

\[x = 6\frac{1}{6}\]

\[Ответ:x = 6\frac{1}{6}.\]