Решебник по алгебре 7 класс Мерзляк Задание 458

\[\boxed{\text{458\ (458).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[- 7x \cdot (x - 6) = 0\]

\[x = 0\ \ или\ \ x - 6 = 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 6.\]

\[Ответ:x = 0;6.\]

\[2)\frac{1}{3} \cdot \left( 12 + x^{3} \right) = \frac{1}{9}x^{2} + 4\]

\[4 + \frac{1}{3}x^{3} - \frac{1}{9}x^{2} - 4 = 0\]

\[\frac{1}{3}x^{3} - \frac{1}{9}x^{2} = 0\]

\[\frac{1}{3}x^{2} \cdot \left( x - \frac{1}{3} \right) = 0\]

\[x = 0\ \ или\ \ x - \frac{1}{3} = 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = \frac{1}{3}.\]

\[Ответ:x = 0;\frac{1}{3}\text{.\ }\]