Решебник по алгебре 7 класс Мерзляк ФГОС Задание 1192

 

\[\boxed{\text{1192\ (1192).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ (x - 2)\left( x^{2} + 2x + 4 \right) =\]

\[= x^{3} + 24x\]

\[x^{3} - 8 = x^{3} + 24x\]

\[24x = - 8\]

\[x = - \frac{1}{3}\]

\[Ответ:\ x = - \frac{1}{3}.\]

\[27 - 8x^{3} - 2x \cdot \left( 25 - 4x^{2} \right) = 7\]

\[27 - 8x^{3} - 50x + 8x^{3} = 7\]

\[- 50x = - 20\]

\[x = \frac{2}{5}\]

\[Ответ:x = \frac{2}{5}\text{.\ }\]

\[\boxed{\text{1192.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[2x - 3y = - 6\ \ \ \ \ и\ \ \ \ \]

\[\ 4x + y = a;\ \ \ \ y = 0\]

\[2x - 3 \cdot 0 = - 6\]

\[2x = - 6\]

\[x = - 3.\]

\[4x + y = a\text{\ \ }\]

\[4 \cdot ( - 3) + 0 = a \Longrightarrow \ \ a = - 12\]

\[Ответ:a = - 12.\]