Решебник по алгебре 7 класс Мерзляк Задание 1177

\[\boxed{\text{1177\ (1177).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ 36x^{2} - (3x - 27)^{2} = 0\]

\[(6x - 3x + 27)(6x + 3x - 27) =\]

\[= 0\]

\[(3x + 27)(9x - 27) = 0\]

\[3x = - 27,\ \ 9x = 27\]

\[\ \ x = - 9\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 3\]

\[Ответ:\ x = - 9;3.\]

\[2)\ (4x - 7)^{2} - (2x + 17)^{2} = 0\]

\[(2x - 24)(6x + 10) = 0\]

\[2x = 24,\ \ 6x = - 10\]

\[\ \ \ x = 12\ \ \ \ \ \ \ \ \ \ \ \ x = - \frac{5}{3} = - 1\frac{2}{3}\]

\[Ответ:x = 12;\ - 1\frac{2}{3}\text{.\ }\]