\[\lg\left( x^{2} + 8x + 15 \right)\]
\[x^{2} + 8x + 15 \leq 0\]
\[D = 64 - 60 = 4\]
\[x_{1} = \frac{- 8 - 2}{2} = - 5;\]
\[x_{2} = \frac{- 8 + 2}{2} = - 3;\]
\[(x + 5)(x + 3) \leq 0\]
\[- 5 \leq x \leq - 3.\]
\[Ответ:\ \ x \in \lbrack - 5;\ - 3\rbrack.\]