\[P(A) = 1 - P\left( \overline{A} \right) = 1 - \frac{C_{18}^{3}}{C_{22}^{3}} =\]
\[= 1 - \frac{18!}{3!(18 - 3)!}\ :\frac{22!}{3!(22 - 3)!} =\]
\[= 1 - \frac{18 \bullet 17 \bullet 16 \bullet 15!}{3 \bullet 2 \bullet 15!} \bullet \frac{3 \bullet 2 \bullet 19!}{22 \bullet 21 \bullet 20 \bullet 19!} =\]
\[= 1 - \frac{4896}{9240} = \frac{4344}{9240} = \frac{181}{385}.\]
\[Ответ:\ \ \frac{181}{385}.\]