Решебник по алгебре и начала математического анализа 11 класс Колягин Задание 515

\[n = 3 + 4 + 5 = 12.\]

\[1)\ m = 3;\]

\[P(A) = \frac{m}{n} = \frac{3}{12} = \frac{1}{4}.\]

\[2)\ m = 4;\]

\[P(A) = \frac{m}{n} = \frac{4}{12} = \frac{1}{3}.\]

\[3)\ m = 5;\]

\[P(A) = \frac{m}{n} = \frac{5}{12}.\]

\[4)\ m = 3 + 4 = 7;\]

\[P(A) = \frac{m}{n} = \frac{7}{12}.\]

\[5)\ m = 3 + 5 = 8;\]

\[P(A) = \frac{m}{n} = \frac{8}{12} = \frac{2}{3}.\]

\[6)\ m = 5 + 4 = 9;\]

\[P(A) = \frac{m}{n} = \frac{9}{12} = \frac{3}{4}.\]

\[7)\ m = 3 + 4 + 5 = 12;\]

\[P(A) = \frac{m}{n} = \frac{12}{12} = 1.\]

\[8)\ m = 0;\]

\[P(A) = \frac{m}{n} = \frac{0}{12} = 0;\]

\[Ответ:\ \ 0.\]