Решебник по алгебре и начала математического анализа 11 класс Колягин Задание 144

\[1)\ f(x) = \frac{1}{x^{2} - 4}\]

\[x^{2} - 4 = 0\]

\[x^{2} = 4\]

\[x = \pm 2.\]

\[Ответ:\ \ x = - 2;\ x = 2.\]

\[2)\ f(x) = \frac{x + 1}{2x + 3}\]

\[2x + 3 = 0\]

\[2x = - 3\]

\[x = - 1,5.\]

\[Ответ:\ \ x = - 1,5.\]

\[3)\ f(x) = \frac{1}{x^{2} + x - 2}\]

\[x^{2} + x - 2 = 0;\]

\[D = 1 + 8 = 9\]

\[x_{1} = \frac{- 1 - 3}{2} = - 2;\]

\[x_{2} = \frac{- 1 + 3}{2} = 1.\]

\[Ответ:\ \ x = - 2;\ x = 1.\]

\[4)\ f(x) = \frac{1}{x^{2} - |x|}\]

\[x^{2} - |x| = 0\]

\[|x| \bullet \left( |x| - 1 \right) = 0\]

\[x = 0\]

\[x = \pm 1.\]

\[Ответ:\ \ x = - 1;\ x = 0;\ x = 1.\]