Решебник по алгебре и начала математического анализа 11 класс Алимов Задание 811

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\[1)\ f(x) = (x - 1)^{8} \bullet (2 - x)^{7}\]

\[= 8 \bullet 0^{7} \bullet 1^{7} - 7 \bullet 0^{8} \bullet 1^{6} = 0.\]

\[2)\ f(x) = (2x - 1)^{5} \bullet (1 + x)^{4}\]

\[= 10 \bullet 1^{4} \bullet 2^{4} + 4 \bullet 1^{5} \bullet 2^{3} =\]

\[= 10 \bullet 16 + 4 \bullet 8 =\]

\[= 160 + 32 = 192.\]

\[3)\ f(x) = \sqrt{2 - x} \bullet (3 - 2x)^{8}\]

\[= - \frac{1^{8}}{2\sqrt{1}} - 16\sqrt{1} \bullet 1^{7} =\]

\[= - \frac{1}{2} - 16 = - 16,5.\]

\[4)\ f(x) = (5x - 4)^{6} \bullet \sqrt{3x - 2}\]

\[= 30 \bullet 1^{5} \bullet \sqrt{1} + \frac{3 \bullet 1^{6}}{2\sqrt{1}} =\]

\[= 30 + \frac{3}{2} = 31,5.\]