\[\boxed{\mathbf{1514}\mathbf{.}}\]
\[f(x) = x^{- 2} + \cos x;\]
\[F(x) = \frac{x^{- 1}}{- 1} + \sin x =\]
\[= - \frac{1}{x} + \sin x + C.\]
\[M\left( 0,5\pi;\ - \frac{2}{\pi} \right):\]
\[- \frac{2}{\pi} = - \frac{1}{0,5\pi} + \sin\left( \frac{\pi}{2} \right) + C\]
\[- \frac{2}{\pi} = - \frac{2}{\pi} + 1 + C\]
\[0 = 1 + C\]
\[C = - 1.\]
\[Ответ:\ \ F(x) = \sin x - \frac{1}{x} - 1.\]