Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 93

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\[1)\ \sqrt{1\frac{9}{16} \cdot 49} = \sqrt{\frac{25}{16} \cdot 49} =\]

\[= \frac{5}{4} \cdot 7 = \frac{35}{4} = 8\frac{3}{4} = 8,75\]

\[2)\ \sqrt{\frac{3}{5}} \cdot \sqrt{5\frac{2}{5}} = \sqrt{\frac{3}{5} \cdot \frac{27}{5}} =\]

\[= \sqrt{\frac{81}{25}} = \frac{9}{5} = 1,8\]

\[3)\ \sqrt{\frac{16 \cdot 1,69}{90\ 000}} = \frac{4 \cdot 1,3}{300} =\]

\[= \frac{2,6}{150} = \frac{1,3}{75} = \frac{13}{750}\]

\[4)\ \frac{2\sqrt{8}}{\sqrt{392}} = 2 \cdot \sqrt{\frac{8}{392}} =\]

\[= 2 \cdot \sqrt{\frac{1}{49}} = 2 \cdot \frac{1}{7} = \frac{2}{7}\]

\[5)\ \sqrt{8^{4}} = 8^{2} = 64\]

\[6)\ \sqrt{( - 4)^{6}} = \sqrt{4^{6}} = 4^{3} = 64\]