Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 145

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\[y = x^{2} + px + q\]

\[x_{0} = - \frac{p}{2} \rightarrow p = - 2x_{0};\]

\[y_{0} = x_{0}^{2} + px_{0} + q \rightarrow q =\]

\[= y_{0} - x_{0}^{2} - px_{0}.\]

\[1)\ x_{0} = 1;y_{0} = 0:\]

\[p = - 2 \cdot 1 = - 2;\]

\[q = 0 - 1^{2} - ( - 2) \cdot 1 = 1.\]

\[2)\ x_{0} = - 2;\ \ y_{0} = 0:\]

\[p = - 2 \cdot ( - 2) = 4;\]

\[q = 0 - 4 + 8 = 4.\]

\[3)\ x_{0} = - 1;\ \ y_{0} = 2:\]

\[p = - 2 \cdot ( - 1) = 2;\]

\[q = 2 - 1 + 2 = 3.\]

\[4)\ x_{0} = 1;\ \ y_{0} = - 2:\]

\[p = - 2 \cdot 1 = - 2;\]

\[q = - 2 - 1 + 2 = - 1.\]