\[q = - \frac{1}{2}\]
\[\frac{b_{7} \cdot b_{9}}{b_{8} \cdot b_{10}} = \frac{b_{1}q^{6} \cdot b_{1}q^{8}}{b_{1}q^{7} \cdot b_{1}q^{9}} = \frac{q^{14}}{q^{16}} =\]
\[= \frac{1}{q^{2}} = \frac{1}{\left( - \frac{1}{2} \right)^{2}} = \frac{1}{\frac{1}{4}} = 4\]
\[Ответ:4.\]