\[\left( - \frac{1}{4} \right)^{3} + \left( 1\frac{1}{2} \right)^{3} = - \frac{1}{64} + \left( \frac{3}{2} \right)^{3} =\]
\[= - \frac{1}{64} + \frac{27}{8} = - \frac{1}{64} + 3\frac{3^{\backslash 8}}{8} =\]
\[= 3\frac{24}{64} - \frac{1}{64} = 3\frac{23}{64}.\]