\[\left( \frac{3a^{3}}{b^{- 2}} \right)^{- 3}\ :\left( \frac{a^{- 4}}{3b^{3}} \right)^{2} =\]
\[= \left( \frac{1}{3} \right)^{3} \cdot \frac{a^{- 9}}{b^{6}}\ :\left( \frac{a^{- 8}}{9b^{6}} \right) =\]
\[= \frac{1}{27a^{9}b^{6}} \cdot 9b^{6}a^{8} = \frac{1}{3a}\text{.\ }\]