\[{5\sqrt{24} > \ \frac{2}{3}\sqrt{54} }{5\sqrt{24} = 5\sqrt{4 \cdot 6} = 5 \cdot 2\sqrt{6} = 10\sqrt{6}}\]
\[\frac{2}{3}\sqrt{54} = \frac{2}{3}\sqrt{9 \cdot 6} = \frac{2}{3} \cdot 3\sqrt{6} = 2\sqrt{6}\]
\[10\sqrt{6} > 2\sqrt{6}.\]