Решите уравнение: (x-2y)^2+(x+2)^2=0.

\[(x - 2y)^{2} + (x + 2)^{2} = 0\]

\[\left\{ \begin{matrix} x - 2y = 0 \\ x + 2 = 0\ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 2 = 2y \\ x = - 2\ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = - 1 \\ x = - 2 \\ \end{matrix} \right.\ \]

\[Ответ:( - 2;\ - 1).\]