Решите уравнение: (x-2y+1)^2+x^2-6xy+9y^2=0.

\[\left\{ \begin{matrix} (x - 3y)^{2} = 0\ \ \\ x - 2y + 1 = 0 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} x - 3y = 0\ \ \ \ \ \ \ \\ x - 2y + 1 = 0 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - y = 1\ \ \ \ \ \ \ \\ x = 2y - 1 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = - 1 \\ x = - 3 \\ \end{matrix} \right.\ \]

\[Ответ:( - 3;\ - 1).\]