Решите уравнение: x^4-3x^2+2=0.

\[x^{4} - 3x^{2} + 2 = 0\]

\[x^{2} = y \geq 0:\]

\[y^{2} - 3y + 2 = 0\]

\[y_{1} + y_{2} = 3;\ \ y_{1} \cdot y_{2} = 2\]

\[y_{1} = 1;\ \ y_{2} = 2.\]

\[1)\ x^{2} = 1\]

\[x = \pm 1.\]

\[2)\ x^{2} = 2\]

\[x = \pm \sqrt{2}.\]

\[Ответ:x = \pm 1;x = \pm \sqrt{2}.\]