Решите уравнение: x^3-2x^2-9x+18=0.

\[x³ - 2x^{2} - 9x + 18 = 0\]

\[x^{2}(x - 2) - 9 \cdot (x - 2) = 0\]

\[(x - 2)(x - 3)(x + 3) = 0\]

\[x = 2,\ \ x = 3,\ \ x = - 3\]

\[Ответ:x = 2;\ x = \pm 3.\]