Решите уравнение: x^3+4x^2-4x-16=0.

\[x^{3} + 4x^{2} - 4x - 16 = 0\]

\[x^{2}(x + 4) - 4(x + 4) = 0\]

\[(x + 4)\left( x^{2} - 4 \right) = 0\]

\[x + 4 = 0\]

\[x = - 4.\]

\[x^{2} - 4 = 0\]

\[x^{2} = 4\]

\[x = \pm 2.\]

\[Ответ:x = - 4;\ \ x = \pm 2.\]