Решите уравнение: x^2/(2-x)=3x/(2-x).

\[\frac{x^{2}}{2 - x} = \frac{3x}{2 - x}\]

\[ОДЗ:\ \ 2 - x
eq 0\]

\[\ \ \ \ \ \ \ \ \ \ \ x
eq 2\]

\[x² = 3x\]

\[x² - 3x = 0\]

\[x(x - 3) = 0\]

\[x = 0\ \ \ \ \ \ \ \ x - 3 = 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 3\]

\[Ответ:x = 0\ \ и\ \ x = 3.\]