Решите уравнение: x^2-8x+15=0.

\[x² - 8x + 15 = 0\]

\[D = ( - 8)^{2} - 4 \cdot 1 \cdot 15 =\]

\[= 64 - 60 = 4\]

\[x_{1} = \frac{8 + \sqrt{4}}{2 \cdot 1} = \frac{8 + 2}{2} = \frac{10}{2} = 5;\]

\[x_{2} = \frac{8 - \sqrt{4}}{2 \cdot 1} = \frac{8 - 2}{2} = \frac{6}{2} = 3.\]

\[Ответ:x = 5;x = 3.\]