Решите уравнение: 6p^2-p-2=0.

\[6p² - p - 2 = 0\]

\[D = ( - 1)^{2} - 4 \cdot 6 \cdot ( - 2) =\]

\[= 1 + 48 = 49\]

\[p_{1} = \frac{1 + \sqrt{49}}{2 \cdot 6} = \frac{1 + 7}{12} = \frac{8}{12} = \frac{2}{3}\]

\[p_{2} = \frac{1 - \sqrt{49}}{2 \cdot 6} = \frac{1 - 7}{12} =\]

\[= - \frac{6}{12} = - 0,5\]

\[Ответ:p = \frac{2}{3};\ p = - 0,5.\]