Решите уравнение (x^2-4)/3-(6-x)/2=3.

\[\frac{x^{2} - 4}{3} - \frac{6 - x}{2} = 3\ \ \ \ \ \ | \cdot 6\]

\[2 \cdot \left( x^{2} - 4 \right) - 3 \cdot (6 - x) = 18\]

\[2x^{2} - 8 - 18 + 3x - 18 = 0\]

\[2x^{2} + 3x - 44 = 0\]

\[D = 9 + 352 = 361\]

\[x_{1} = \frac{- 3 + 19}{4} = 4;\ \ \ \]

\[x_{2} = \frac{- 3 - 19}{4} = - 5,5.\]

\[Ответ:x = - 5,5;\ \ x = 4.\]