Решите уравнение: (x^2-3x-10)/(x-5)=0.

\[\frac{x^{2} - 3x - 10}{x - 5} = 0\]

\[x^{2} - 3x - 10 = 0\]

\[D = ( - 3)^{2} - 4 \cdot 1 \cdot ( - 10) =\]

\[= 9 + 40 = 49\]

\[\ x_{1} = \frac{3 + \sqrt{49}}{2} = \frac{3 + 7}{2} = \frac{10}{2} = 5\]

\[x_{2} = \frac{3 - \sqrt{49}}{2} = \frac{3 - 7}{2} = \frac{- 4}{2} =\]

\[= - 2\]

\[x + 2 = 0\ \ \]

\[\ x = - 2\]

\[Ответ:\ x = - 2.\]