Решите уравнение: x^2+2005x-2006=0.

\[x^{2} + 2005x - 2006 = 0\]

\[D = 2005^{2} - 4 \cdot 1 \cdot (2006) =\]

\[= 4\ 020\ 025 + 8024 =\]

\[= 4\ 028\ 049\]

\[\sqrt{D} = \sqrt{4028049} = 2007\]

\[x_{1} = \frac{- 2005 + 2007}{2} = \frac{2}{2} = 1\]

\[x_{2} = \frac{- 2005 - 2007}{2} =\]

\[= \frac{- 4012}{2} = - 2006\]

\[Ответ:1;\ - 2006.\]