\[(x + 8)(x - 8) - 4 \cdot (x - 4) =\]
\[= 2x - 56\]
\[x^{2} - 64 - 4x + 16 - 2x + 56 =\]
\[= 0\]
\[x^{2} - 6x + 8 = 0\]
\[x_{1} + x_{2} = 6;\ \ \ x_{1} \cdot x_{2} = 8\]
\[x_{1} = 4\ (не\ подходит),\ \ \]
\[x_{2} = 2\]
\[Ответ:x = 2.\]