Решите уравнение: (x+2)^3-x^2*(x+5)-(x+1)(x-1)=0.

\[(x + 2)^{3} - x^{2}(x + 5) - (x + 1)(x - 1) = 0\]

\[x^{3} + 6x^{2} + 12x + 8 - x^{3} - 5x^{2} - x^{2} + 1 = 0\]

\[12x + 9 = 0\]

\[12x = - 9\]

\[x = - \frac{9}{12} = - \frac{3}{4}\]

\[x = - 0,75.\]