Решите уравнение: 9x^4-24x^2+16=0.

\[9x^{4} - 24x^{2} + 16 = 0\]

\[\left( 3x^{2} - 4 \right)^{2} = 0\]

\[3x^{2} - 4 = 0\]

\[3x^{2} = 4\]

\[x^{2} = \frac{4}{3}\]

\[x = \pm \sqrt{\frac{4}{3}} = \pm \frac{2}{\sqrt{3}} = \pm \frac{2\sqrt{3}}{3}.\]

\[Ответ:x = \pm \frac{2\sqrt{3}}{3}.\]